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Question:Given the root pointer to a binary tree, find the sum of all its elements.

Input:Sample Tree (Pointer to node 1 is given).

Output:Sum = 15

This is a very simple problem. Since the tree follows a recursive sub-structure, we can recursively call left tree sum, right tree sum and then add their values to the current node data.

#include<stdio.h> #include<malloc.h> struct binaryTreeNode{ int data; struct binaryTreeNode * left; struct binaryTreeNode * right; }; int sumOfBinaryTree(struct binaryTreeNode * root) { // Terminating condition if(root == NULL) { return 0; } else { //Recursively call the addition of root + left + right return (root -> data + sumOfBinaryTree(root -> left) + sumOfBinaryTree(root -> right)); } }