*725*

Question:Given 2 binary trees, determine if they are mirror of each other

Input:2 tree pointers are given. (Root pointer)

Output:TRUE

We can again apply the recursive sub-structure property of the tree here. The algorithm can be implemented as:-

#include<stdio.h> #include<malloc.h> struct binaryTreeNode{ int data; struct binaryTreeNode * left; struct binaryTreeNode * right; }; int areTreeMirrors(struct binaryTreeNode * root1, struct binaryTreeNode * root2) { // Terminating condition if(root1 == NULL && root2 == NULL) return 1; //If one of them is NULL, then they are definitely not mirrors if(root1 == NULL || root2 == NULL) return 0; //If one of them is different, then also they are not mirrors if(root1 -> data != root2 -> data) { return 0; } else { // Compare the left and right nodes of the trees return (areTreeMirrors(root1 -> left, root2 -> right) && areTreeMirrors(root1 -> right, root2 -> left)); } }

*Time Complexity:-* O(n)

*Space Complexity:-* O(n) due to a recursive stack