Question: We have 2 sorted arrays and we want to combine them into a single sorted array.
Input: arr1[] = 1, 4, 6, 8, 13, 25 || arr2[] = 2, 7, 10, 11, 19, 50
Output: 1, 2, 4, 6, 7, 8, 10, 11, 13, 19, 50
One of the simplest ways to solve this problem would be to copy both the arrays into a new array and then apply some sorting technique on them. But this method will not utilize the fact that both the arrays are already sorted.
We need to apply a different approach. Here is the algorithm that we can implement.
- Initialize two variables that serve as an index to both the arrays.
- Let i point to arr1[] and j point to arr2[].
- Compare arr[i] and arr[j]
- Add the smaller element to the new array and increase the counter.
- Repeat these steps until both counters i & j have reached the end.
Here is an implementation of the above algorithm
#include<stdio.h>
//a function to merge two arrays
//array1 is of size 'l'
//array2 is of size 'm'
//array3 is of size n=l+m
void merge(int arr1[], int arr2[], int arr3[], int l, int m, int n)
{
//3 counters to point at indexes of 3 arrays
int i,j,k;
i=j=k=0;
//loop until the array 1 and array 2 are within bounds
while(i<l && j<m)
{
//find the smaller element among the two
//and increase the counter
if(arr1[i] < arr2[j])
{
arr3[k] = arr1[i];
//increment counter of 1st array
i++;
}
else
{
arr3[k] = arr2[j];
//increment counter of second array
j++;
}
//increase the counter of the final array
k++;
}
//now fill the remaining elements as it is since they are
//already sorted
while(i<l)
{
arr3[k] = arr1[i];
i++;
k++;
}
while(j<m)
{
arr3[k] = arr2[j];
j++;
k++;
}
}
//driver program to test the above function
int main(void)
{
int arr1[5] = {1, 5, 9, 11, 15};
int arr2[5] = {2, 4, 13, 99, 100};
int arr3[10] = {0};
merge(arr1, arr2, arr3, 5, 5, 10);
int i=0;
for(i=0;i<10;i++)
printf("%d ",arr3[i]);
return 0;
}
